Answer to Question #142951 in Statistics and Probability for Margaret

Statistics and Probability

Question #142951

Consider a poison distribution with a mean ¡=3 then P( X<2) is
1. 0.2240
2. 0.1992
3. 0.4232
4. 0.1494
5. 0.4223

Expert's answer

$P( X<2)=P( X=0)+P( X=1)\\ =\frac{e^{-3}3^{0}}{0!}+\frac{e^{-3}3^{1}}{1!}\\ \approx 0.1992$

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