A - student gets ticket №10
If in the first turn:
p(A) = 1/25 = 0.04
If in the second turn:
p(A) = p(probability of getting ticket №10 in case the first student doesn't get ticket №10)*p(the first student doesn't get ticket №10)
p(A) = 1/24*24/25 = 1/25 = 0.04
If in the third turn:
p(A) = p(probability of getting ticket №10 in case the first and the second students don't get ticket №10)*p(the first student doesn't get ticket №10)*p(the second student doesn't get ticket №10)
p(A) = 1/23*24/25*23/24 = 1/25 = 0.04
Answer: it does not matter
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