Let
probability of needing an oil be O
probability of needing an oil filter be F
P(O)=0.25P(O)=0.25P(O)=0.25
P(F)=0.40P(F)=0.40P(F)=0.40
P(O∩F)=0.14P(O\cap F)=0.14P(O∩F)=0.14
a. P(O∣F)P(O|F)P(O∣F)
P(O∣F)=P(O∩F)P(F)P(O|F)=\frac{P(O\cap F)}{P(F)}P(O∣F)=P(F)P(O∩F)
=0.140.4=0.35=\frac{0.14}{0.4}=0.35=0.40.14=0.35
b. P(F∣O)P(F|O)P(F∣O)
P(F∣O)=P(O∩F)P(O)P(F|O)=\frac{P(O\cap F)}{P(O)}P(F∣O)=P(O)P(O∩F)
=0.140.25=0.56=\frac{0.14}{0.25}=0.56=0.250.14=0.56
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