Probability of having a car rented from different agencies denoted by P, Q:
P(P) = 0.45
P(Q) = 0.55
Probability of having a car with bad tyres denoted by bad given corresponding agency:
P(bad|P) = 0.08
P(bad|Q) = 0.06
Hence:
P(good|P) = 1 – 0.08 = 0.92
P(good|Q) = 1 – 0.06 = 0.94
Probability of having a car with a good tyres coming from agency Q is denoted P(Q|good).
"P(Q|good)=\\frac{P(Q\\cap good)}{P(good)}=\\frac{0.55\\cdot0.94}{0.55\\cdot0.94+0.45\\cdot0.92}=0.56"
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