Assume that the travel times are normally distributed.
a. P(X≥180)P(X\ge180)P(X≥180)
μ=200,σ=10\mu=200,\sigma=10μ=200,σ=10
P(X≥180)=P(Z≥180−20010)P(X\ge180)=P(Z\ge\frac{180-200}{10})P(X≥180)=P(Z≥10180−200)
=P(Z≥−2)=P(Z\ge-2)=P(Z≥−2)
=1−P(Z≤−2)=1-P(Z\le-2)=1−P(Z≤−2)
=1−0.02275=1-0.02275=1−0.02275
=0.97725=0.97725=0.97725
b. P(X≤205)P(X\le205)P(X≤205)
P(X≤205)=P(Z≤205−20010)P(X\le205)=P(Z\le\frac{205-200}{10})P(X≤205)=P(Z≤10205−200)
=P(Z≤0.5)=0.6915=P(Z\le0.5)=0.6915=P(Z≤0.5)=0.6915
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