n = 500
p = sample proportion of rice eaters
p= 280/500=0.56
P = population proportion of rice eaters
P= 1/2 = 0.5
Q =1-P=1-0.5=0.5
Null hypothesis
Both rice and wheat eaters are equally popular in the state
H0 : P=0.5
Alternative hypothesis H1: P "\\not =" 0.5
(two tailed test)
z=(p-P)/ "\\sqrt{\\frac{P*Q}{n}}" =(0.56-0.5)/"\\sqrt{\\frac{0.5*0.5}{500}}" =2.68
The calculated value of z=2.68
The tabulated value of z at 1% level of significance for two-tailed test is 2.58.
Since calculated z> tabulated z, we reject the Null Hypothesis H0 at 1% level of significance and conclude that rice and wheat are not equally popular in the district
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