Solution
first, we obtain the P(60<x<70)
x~N(64,102)
"= \\phi({70-64 \\over 10})- \\phi({60-64 \\over 10})= \\phi(0.6) - \\phi (-0.4)""= 0.7257 - 0.3446=0.3811"
This implies that 0.3811 or 38.11% of the students scored between 60 and 70.
But we know that 40 students scored between 60 and 70, therefore, the total number of students who took the examination is:
"\\therefore 105" students took the examination
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