Solution
first, we obtain the P(60<x<70)
x~N(64,102)
P(60<x<70)=P(x<70)−P(x<60)
=ϕ(1070−64)−ϕ(1060−64)=ϕ(0.6)−ϕ(−0.4)=0.7257−0.3446=0.3811 This implies that 0.3811 or 38.11% of the students scored between 60 and 70.
But we know that 40 students scored between 60 and 70, therefore, the total number of students who took the examination is:
=0.38111∗40=104.96≈105 ∴105 students took the examination
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