Question #139878
What is the probability that Mike spends at most 240 min on online gaming if his mean time spent on it is 270 min with a standard deviation time of 15 min?
1
Expert's answer
2020-10-27T18:42:27-0400

Let's assume that time spent is normally distributed.

P(x<240)=P(z<240−27015)P(x<240)=P(z<\frac{240-270}{15})

=P(z<−2)=0.0228=P(z<-2)=0.0228



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