Given : μ=10σ=2\mu=10\\ \sigma=2μ=10σ=2
n=100
Formula: Z=x‾−μσnZ= \frac{\overline x-\mu}{\frac{\sigma}{\sqrt{n}}}Z=nσx−μ
Solution:
substitute the values to find z
Z=9.7−102100Z= \frac{9.7-10}{\frac{2}{\sqrt{100}}}Z=10029.7−10 −1.5
Using z table,Pr(x‾≤9.7)=Pr(Z≤−1.5)=0.0668Pr( \overline x≤9.7)=Pr(Z≤−1.5)=0.0668Pr(x≤9.7)=Pr(Z≤−1.5)=0.0668
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