Question #139725
II. Given sigma μ=45 and σ, = 6, determine and plot the location of the z scores of the following raw scores: 56, 70,82
III. The scores of SLU College Admission Test are normally distributed,with = 80 and = 6. Find the following:
1. What is the percentile rank of 84?
2. What percentageof scores fall between 64 and 90?
1
Expert's answer
2020-10-22T18:17:46-0400
Z=xμσZ=\frac{x-\mu}{\sigma}

Part I)


μ=45, σ=6\mu = 45, \ \sigma=6

When X = 56,


Z=56456=1.8333Z=\frac{56-45}{6}= 1.8333

When X = 70


Z=70456=4.1667Z=\frac{70-45}{6}=4.1667

When X = 82



Z=83456=6.1667Z=\frac{83-45}{6}=6.1667




Part II)



μ=80, σ=6\mu =80,\ \sigma =6

1.) At 84,



Z=84806=0.6667Z=\frac{84-80}{6}=0.6667

At Z= 0.6667, probability is 0.74752.


The percentile score 74.752


2. Between 64 and 90



64806<Z<90806\frac{64-80}{6} < Z < \frac{90-80}{6}

2.6667<Z<1.6667-2.6667<Z<1.6667

The corresponding probability is


P(Z<1.6667)P(Z>2.6667)P(Z<1.6667)-P(Z>-2.6667)

0.952210.00383=0.948380.95221-0.00383=0.94838

the probability is 0.9484

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