Question #139424

The weights of a women population are normally distributed with mean 60kg and standard deviation 5kg. Find the probability that the weight of a woman chosen at random is between 61 and 65kg.

Expert's answer

μ=60\mu = 60

σ=5\sigma = 5

P(61<X<65)=P(61−μσ<Z<65−μσ)=P(61−605<Z<65−605)=P(0.2<Z<1)=P(Z<1)−P(Z<0.2)=0.8413−0.5793=0.262P(61<X<65)=P( \frac{61-\mu}{\sigma}<Z<\frac{65-\mu}{\sigma})=P( \frac{61-60}{5}<Z<\frac{65-60}{5})=P(0.2<Z<1) = P(Z<1) -P(Z<0.2)=0.8413-0.5793=0.262

Answer: the probability that the weight of a woman chosen at random is between 61 and 65kg is 26.2%


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