The probability that a senior actually goes to college is 0.7. We use a binomial distribution and receive: p=C1513(0.7)13(0.3)2+C1514(0.7)14(0.3)+C1515(0.7)15≈0.11157p=C_{15}^{13}(0.7)^{13}(0.3)^2+C_{15}^{14}(0.7)^{14}(0.3)+C_{15}^{15}(0.7)^{15}\approx0.11157p=C1513(0.7)13(0.3)2+C1514(0.7)14(0.3)+C1515(0.7)15≈0.11157
The latter is rounded to 5 decimal places.
Answer: 0.11157
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