Given : n= 18
r= 2
solution:
since order matters here, we use permutation.
formula:
npr= "\\frac{n!}{(n-r)!)}"
Hence 18P2 ="\\frac{18!}{(18-2)!}" = 306 ways in total
number of ways selecting two = 1(since order matters)
Hence required probability = "\\frac{1}{306}"
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