Solution
Let lifetime of bulbs be x
X~N(1150,1752)
Pr(x>1000)=1-Pr(x<1000)
Obtaining the z-score of the above yields :
Φ(1751000−1150)=Φ(−0.85714)
Which follows x~N(0,1)
We can thus obtain the probability from statical tables.
Φ(−0.85714)=0.1957
1−Φ(−0.85714)=0.8043
Ans : 0.8043
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