Let X= the length of treatment in days: X∼N(μ,σ2)
Then Z=σX−μ∼N(0,1)
Given μ=183 days,σ=14 days
P(X<160)=P(Z<14160−183)≈
≈P(Z<−1.642857)≈0.050206 The probability that a person will be healthy and TB free in less than 160 days is approximately 5.0206 %.
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