Let "X=" the length of treatment in days: "X\\sim N(\\mu, \\sigma^2 )"
Then "Z=\\dfrac{X-\\mu}{\\sigma}\\sim N(0, 1)"
Given "\\mu=183\\ days, \\sigma=14\\ days"
"\\approx P(Z<-1.642857)\\approx0.050206"
The probability that a person will be healthy and TB free in less than 160 days is approximately "5.0206\\ \\%."
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