solution
Population proportion, "p=0.12"
Sample proportion, "\\hat p=0.11"
"\\frac{0.11 -0.12}{\\sqrt{\\frac{0.12(1-0.12)}{412}}}=-0.6246"
When the Z score is -0.6246, the probability that "Z>-0.6246" is "0.73388"
answer:
The probability that the proportion is greater than 0.11 is 0.7339
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