Condition probability. A deck of cards has 26 black card.
P(B1)=2652=12P(B_1)=\frac{26}{52}=\frac{1}{2}P(B1)=5226=21
P(B2/B1)=2551P(B_2/B_1)=\frac{25}{51}P(B2/B1)=5125
P(B1B2)=12×2551=25102P(B_1B_2)=\frac{1}{2}×\frac{25}{51}=\frac{25}{102}P(B1B2)=21×5125=10225
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