Answer to Question #136269 in Statistics and Probability for Surprise Nxumalo

Question

The rate at which cars arrive at the garage is 12 cars per hour. If the arrival of cars at the garage is assumed to follow a poisson distribution, 1 what is the probability that in the next hour there will be at at most 1 car arriving at the garage

Answer 1

$P(x)=\frac{e^{-12}(12)^{x}}{x!}, x=0,1,2,...\\ P(x\leq1)=P(x=0)+P(x=1)\\ =\frac{e^{-12}(12)^{0}}{0!}+\frac{e^{-12}(12)^{1}}{1!}\approx 0.0000799$