We need to choose 3 medallists among 6 athletes. Since all medals are different, we can do it in
C(6,3)=(63)=6!3!3!=4⋅5⋅61⋅2⋅3=20\displaystyle C(6,3) = \begin{pmatrix}6\\3\end{pmatrix}=\frac{6!}{3!3!} = \frac{4 \cdot 5 \cdot 6}{1\cdot 2 \cdot 3} = 20C(6,3)=(63)=3!3!6!=1⋅2⋅34⋅5⋅6=20 ways.
Answer: 20 ways
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