Population standard deviation is known and the sample is large, "\\ge30" , thus, normal distribution is used.
"H_o\\mu=100"
"H_a\\mu\\ne100"
Assume 95% confidence level.
"CV, Z_{0.025}=1.96"
Test statistic"=\\frac{\\bar{X}-\\mu}{\\frac{\\sigma}{\\sqrt{n}}}"
"=\\frac{140-100}{\\frac{15}{\\sqrt{30}}}=14.61"
Since the calculated statistic 14.61 is grater than the critical value, 1.96, we reject the null hypothesis and conclude that the raw cornstarch had an effect on blood glucose level.
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