Null hypothesis "H_0:\\mu=1.0."
Alternative hypothesis "H_a:\\mu\\ne1.0."
Test statistic: "z=\\frac{\\bar x-\\mu}{\\frac{\\sigma}{\\sqrt{n}}}=\\frac{1.2-1.0}{\\frac{0.4}{\\sqrt{12}}}=1.73."
P-value: "p=2P(Z>1.73)=0.0836."
Since the P-value is greater than 0.05, fail to reject the null hypothesis.
There is no significant evidence that the mean serum-creatinine level in this group is
different from that of the general population.
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