Question #131918
If the variance of the performance score of students is 12,5 and the mean is 32,5, what will the standard deviation be
1
Expert's answer
2020-09-07T17:35:16-0400

Standard deviation is a square root of variance:

σ=σ2=12.5=3.54\sigma = \sqrt{\sigma^2} = \sqrt{12.5}=3.54

Answer: 3.54.


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