The probability that a customer will buy a cup of coffee is 0.6. A customer buys a muffin 45% of the time when a cup of coffee is bought, but only 10% of the time when a cup of coffee is not bought.
1. What is the probability of buying a muffin but not a cup of coffee.
2. What is the probability of buying a muffin
Let:
Buying coffee = C
Buying muffin = M
P(C) =0.6
P(M/C)=0.45
P(M/C')=0.1
Solution to Q.1
P(M and C') = P(C').P(M/C')
but P(C') = 1- P(C) = 0.4
Thus, P(M and C')="0.4*0.1 = 0.04"
Answer: 0.04
Solution to Q.2
P(M) = P(C).P(M/C) + P(C').P(M/C')
Answer: 0.31
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