Question #130694

4 items are taken at random from a box of 12 items and inspected. The box is rejected if more than 3 item is found to be faulty. If there are 5 faulty items in the box .Find the probability that the box is rejected.

Expert's answer

Let success be defined as selecting a defective item from the box.


Given that there are 5 defective items in a box of 12 items,


The probability of success p = 5/12 = 0.41666

Probability of failure q = 7/12 = 0.58333


Since we are sampling only 4 items out of 12 items n = 4


Thus probability that the box getting rejected is only when all the 4 items (4 out of 4) on a random selection from the box are found to be defective.


Hence we can find the probability P(x) using the binomial distribution formula,


P(x) = n!(nx)!x!\frac {n!}{(n-x)!*x!}*px*qn-x


P(x) = P(4) = 0.03014


Above is the probability that the box will be rejected.


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