Question

1.    A normal distribution of BMCC MAT51 scores has a standard deviation of 1.5. Find the z-scores corresponding to each of the following values:

 

a.    A score that is 3 points above the mean.

 

b.    A score that is 1.5 points below the mean.  

Answer 1

Given : sd = 1.5

formula:

Z= $\frac{x-mean}{sd}$

Solution:

a.

When score is 3 points above the mean , x-mean= 3

so Z= $\frac{3}{1.5}$ = 2

b.When score is 1.5 points below the mean , x-mean= -1.5

so Z= $\frac{-1.5}{1.5}$ = -1