Question

To develop programs for business travelers staying at conventional hotels, a major hotel chain

commissioned a study of executives who play golf. The study revealed that 55% of the

executives admitted they have cheated at golf. Also, 20% of the executives admitted that they

had cheated at golf and had lied in business. Given an executive who had cheated at golf, what

is the probability the executive also had lied in business?

Answer 1

Let A= executives admitted they have cheated at golf and

B= had lied in business

Given:

P(A)= 0.55

P(A and B)= 0.20

To find :

Given an executive who had cheated at golf, what is the probability the executive also had lied in business.

That is to find P(B/A).

Formula :

P(B/A)= $\frac{P(A and B)}{P(A)}$

solution:

P(B/A)= $\frac{0.2}{0.55}$ = 0.3636 or 36.36%