Question #12776

DISCUSS ANY ONE CONTINUOUS PROBABILITY DISTRIBUTION?

Expert's answer

Question #12776

DISCUSS ANY ONE CONTINUOUS PROBABILITY DISTRIBUTION.

Solution.

Here we will discuss normal distribution N(μ,σ2)N(\mu, \sigma^2). The distribution density function is f(x)=12πσ2e(xμ)22σ2f(x) = \frac{1}{\sqrt{2\pi\sigma^2}} e^{-\frac{(x - \mu)^2}{2\sigma^2}}, x(,+)x \in (-\infty, +\infty). Mean equals μ\mu, variance equals σ2\sigma^2. Characteristic function equals φ(t)=eiμt1/2t2σ2\varphi(t) = e^{i\mu t - 1/2t^2\sigma^2}. If XN(μ,σ2)X \sim N(\mu, \sigma^2) then Xμσ\frac{X - \mu}{\sigma} has standard normal distribution N(0,1)N(0,1). The normal random XX variable with 'big' probability takes values near μ\mu. For instance, P(Xμ3σ)0.0027P(|X - \mu| \geq 3\sigma) \approx 0.0027.

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