Answer to Question #127603 in Statistics and Probability for mehru

Question #127603
A bag contains 14 identical balls, 4 of which are red, 5 black and 5 white. Six balls are drawn from the bag. find the probability that
(i) 3 are red, (ii) at least two are white.
1
Expert's answer
2020-07-27T18:48:45-0400

Solution :

14C6 = 3003 combinations of 14 balls taken 6 at a time.


i)P(3 are red)= (3 red out of 4 red balls) and (3 out of total 10 balls)

4c310C314C6\frac{4c3*10C3}{14C6} =4803003\frac{480}{3003} =0.159


ii)

P(at least two white)=1- [P(0 white)+P(1 white)]

that is P(X2)\geq 2) =1-[P(X=0)+P(x=1)]


= 1- [9C614C6\frac{9C6}{14C6} + 5c19c514C6]\frac{5c1*9c5}{14C6}]


=1-[843003\frac{84}{3003} + 51263003]\frac{5*126}{3003}]


=1-[7143003]\frac{714}{3003}] = 22893003\frac{2289}{3003} =0.7622


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Comments

Assignment Expert
07.09.20, 20:02

Dear hasan, please use the panel for submitting new questions.

hasan
07.09.20, 11:51

Let X have a binomial distribution with n = 4 and P = 1/3 Find the probability. (i) P (X = 1) (ii) P (X = 3/2 ) (iii) P (X = 3) (iv) P (X = 6) (v) P (X ≤ 2) *

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