Answer to Question #127244 in Statistics and Probability for luis

Question

Seventy-five percent of female prison inmates are mothers. If 3 female prison inmates are selected at random, what is the probability that none are mothers? Round the final answer to three decimal places, if necessary.

p(none are mothers)=

Answer 1

Given : p(mother ) = 0.75

Formula : p(Ac)= 1-p(A)

Solution :

P(non mother )=1-p(mother)

=1-0.75

=0.25

Hence p( three are not mothers)= 0.25*0.25*0.25

= 0.0156= 0.016.