A Covid 19 testing machine at a testing centre breaks down an average of three times per year. Using an appropriate probability distribution formula, find the probability that during the next year, this machine will have;
i. exactly two breakdowns
ii. at most one breakdown
solution:
The number of successes in two disjoint time intervals is independent. The probability of a success during a small time interval is proportional to the entire length of the time interval
given : "\\lambda" = 3
Formula: P(X=x)= "\\frac{\\lambda ^{x}e^{\\lambda }}{x!}"
part i)
Exactly two breakdowns
P(x=2)= "\\frac{3 ^{2}e^{3 }}{2!}" = 0.2240
Part ii)
At most one breakdown:
P(X"\\leq" 1)= P(X=0)+P(x=1)
="\\frac{3 ^{0}e^{3 }}{0!}" + "\\frac{3 ^{1}e^{3 }}{1!}"
=0.0498+0.1494
=0.1992
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