let A =error found by test 1
let B=error found by test 2
let C=error found by test 3
Given P(A)=0.2, P(B)=0.3, P(C)=0.5
therefore P(notA)=0.8, P(notB)=0.7, P(notC)=0.5
Note: tests are independent P(notA & notB & notC)=P(notA)*P(notB)*P(notC)=0.8*0.7*0.5=0.28
P(found by at least one test)= 1- P(not found by any test)=1-P(notA & notB & notC)=1-0.28=0.82
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