If a child is given cards with A, C, D, G, O and T on them, what is the probability that he/she could spell DOG by the correct arrangement of 3 cards from 6?
1
Expert's answer
2020-07-01T19:38:16-0400
There are A63=3!6!=4⋅5⋅6=120 different ways of choosing the word that has 3 letters from the set of 6 letters. The probability to receive the word DOG is 1201=0.0083 (it is rounded to 4 decimal places)
Answer: 0.0083 (the answer is rounded to 4 decimal places)
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