Question #123390
Question 1: A company has made available to its employees (without charge) extensive health club facilities that may be used before work, during the lunch hour, after work, and on weekends. Records for the last year indicate that of 250 employees, 110 used the facilities at some time. Of 170 males employed by the company, 65 used the facilities. What is the probability that an employee chosen at random.




d. Is a female or has used the health club facilities?
e. Given that the selected employee is female, what is the probability that she has used the health club facilities?
f. Given that the selected employee is male, what is the probability that he has not used the health club facilities?
1
Expert's answer
2020-06-22T18:14:14-0400
UseDont useTotalFemale453580Male65105170Total110140250\def\arraystretch{1.5} \begin{array}{c:c:c} & Use & Don't \ use & Total\\ \hline Female & 45 & 35 & 80 \\ \hdashline Male & 65 & 105 & 170 \\ \hdashline Total & 110 & 140 &250 \end{array}

d.


P(Female or Use)=P(Female\ or\ Use)=

=P(Female)+P(Use)P(Female and Use)==P(Female)+P(Use)-P(Female\ and\ Use)=

=80250+11025045250=145250=={80 \over 250}+{110 \over 250}-{45 \over 250}={145 \over 250}=

=145250=2950=0.58={145 \over 250}={29 \over 50}=0.58

e.


P(UseFemale)=4580=916=0.5625P(Use|Female)={45\over 80}={9 \over 16}=0.5625

f.


P(Dont useMale)=105170=21340.617647P(Don't\ use|Male)={105 \over 170}={21 \over 34}\approx0.617647



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