Answer to Question #123021 in Statistics and Probability for Rohit kumar prasad

Question

Student population of a university has 30% asian, 40% american, 20% european and 10% african students. It is known that 40% of all asian students, 50% of all american students, 60% of all european students and 20% of all african students are girls. Find the probability that a girl chosen at random from the university is an asian?

Answer 1

Let $A_1$ denote asian student, $A_2$ denote american student, $A_3$ denote european student, $A_4$ denote african student, and $G$ denote that a tudent is a girl.

Given

$P(A_1)=0.3,$

$P(A_2)=0.4,$

$P(A_3)=0.2,$

$P(A_4)=0.1,$

$P(G|A_1)=0.4,$

$P(G|A_2)=0.5,$

$P(G|A_3)=0.6,$

$P(G|A_4)=0.2$

$P(G)=P(A_1)P(G|A_1)+P(A_2)P(G|A_2)+$

$+P(A_3)P(G|A_3)+P(A_4)P(G|A_4)=$

$=0.3(0.4)+0.4(0.5)+0.2(0.6)+0.1(0.2)=0.46$

Use the Bayes' Theorem

$P(A_1|G)=\dfrac{P(A_1)P(G|A_1)}{P(G)}=$ $=\dfrac{0.3(0.4)}{0.46}={6\over 23}\approx0.260870$