The number of power outages follows a Poisson Distribution.
a) P(x=3)=(λxe-λ)/x!=(43e-4)/3!=0.195
b)P(x>2)=1-P(x=0)-P(x=1)-P(x=2)=1-(40e-4)/0!-(41e-4)/1!-(42e-4)/2!=1-0.0183-0.07326-0.1465=0.76194