A lot of 12 television sets chosen at random are defective , if 3 of the sets are chosen at random for shipment in hotel. how many defective set can they expect
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Expert's answer
2020-06-11T16:44:03-0400
Let x denote the number of defective televisions out of the 12. The probability(p) of selecting a defective television is "\\frac {x} {12}"
Mean =np;
="3*\\frac {x} {12}=\\frac {x} {4}"
They should expect "\\frac {x} {4}" defective sets
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