Question

A lot of 12 television sets chosen at random are defective , if 3 of the sets are chosen at random for shipment in hotel. how many defective set can they expect

Answer 1

Let x denote the number of defective televisions out of the 12. The probability(p) of selecting a defective television is $\frac {x} {12}$

Mean =np;

=$3*\frac {x} {12}=\frac {x} {4}$

They should expect $\frac {x} {4}$ defective sets