Let A be the event that the student will get an offer from company A
and B be the event that the student will get an offer from company B
Then A "\\cap" B is the event that he will get offers from both companies
We are given,
P(A) = 0.6, P(B) = 0.45 and P(A "\\cap" B) = 0.35
"\\therefore" The probability that he will get at least one offer from these two companies is
P(A "\\cup" B) = P(A) + P(B) - P(A "\\cap" B) = 0.6 + 0.45 - 0.35 = 0.7
Answer: The probability that the student will get at least one offer from these two companies is 0.7.
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