Z∼N(0,1/2) , μ=0, σ2=1/2
We will use the following properties:
P(X<a)=F(a)=1−F(−a)
P(X>a)=1−F(a)=F(−a)
P(a<X<b)=F(b)−F(a)
F(x)=Φ(σx−μ)
a) P(Z>2)=1−F(2)=1−Φ(22)≈1−Φ(2.82)=1−0.9976=0.0024
b) P(Z<−2)=F(−2)=1−F(2)=0.0024
c) P(−1<Z<0.5)=F(0.5)−F(−1)=Φ(1/2)−Φ(−2)≈Φ(0.70)−Φ(−1.41)=0.7580−0.0793≈0.68
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