"n=10,\\\\\n\\bar x=\\frac{155+179+...+172}{10}=167.3,\\\\\ns^{2}=\\frac{(155-167.3)^{2}+(179-167.3)^{2}+...(172-167.3)^{2}}{9}=65.1222\\\\\ns=\\sqrt{65.122}=8.07\\\\\nH_0: \\mu\\geq179\\\\\nH_1:\\mu <179\\\\\n \\alpha =0.05\\implies t_{(0.05,9)}=1.833,\\\\\nT=\\frac{\\bar x-\\mu_0}{\\frac{s}{\\sqrt n}}\\\\\nT=\\frac{167.3-179}{\\frac{8.07}{\\sqrt {10}}}=-4.585\\\\\n\\text{the rejection region} :\\; t<-1.833\\\\\n\\text{The decision is to reject}:\\; H_0\\\\\n\\text {This mean that there is sufficient evidence to }\\\\\n\\text{ conclude that the average price of the racket is }\\\\\nless \\;than\\; 179"
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