"Given \\; that, \u03bc=60, \u03c3=8, n=200, then,\\\\\n ii) P(x<50)=P(Z<\\frac{50-60}{8})\\\\\n=P(Z<-1.25)=0.5-P(0<Z<1.25)\\\\\n=0.5-0.3944=0.1056\\\\\n number\\;of\\;patients=200\\times0.1056=21.12\\approx22\\\\\nii) P(x>64)=P(Z>\\frac{64-60}{8})\\\\\n=P(Z>0.5)=0.5-P(0<Z<0.5)\\\\\n=0.5-0.1915=0.3085\\\\\n number\\;of\\;=200\\times0.3085=61.7\\approx62\\\\"
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