Given that,μ=60,σ=8,n=200,then,ii)P(x<50)=P(Z<50−608)=P(Z<−1.25)=0.5−P(0<Z<1.25)=0.5−0.3944=0.1056number of patients=200×0.1056=21.12≈22ii)P(x>64)=P(Z>64−608)=P(Z>0.5)=0.5−P(0<Z<0.5)=0.5−0.1915=0.3085number of =200×0.3085=61.7≈62Given \; that, μ=60, σ=8, n=200, then,\\ ii) P(x<50)=P(Z<\frac{50-60}{8})\\ =P(Z<-1.25)=0.5-P(0<Z<1.25)\\ =0.5-0.3944=0.1056\\ number\;of\;patients=200\times0.1056=21.12\approx22\\ ii) P(x>64)=P(Z>\frac{64-60}{8})\\ =P(Z>0.5)=0.5-P(0<Z<0.5)\\ =0.5-0.1915=0.3085\\ number\;of\;=200\times0.3085=61.7\approx62\\Giventhat,μ=60,σ=8,n=200,then,ii)P(x<50)=P(Z<850−60)=P(Z<−1.25)=0.5−P(0<Z<1.25)=0.5−0.3944=0.1056numberofpatients=200×0.1056=21.12≈22ii)P(x>64)=P(Z>864−60)=P(Z>0.5)=0.5−P(0<Z<0.5)=0.5−0.1915=0.3085numberof=200×0.3085=61.7≈62
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