Probability of question correct =15= \frac{1}{5}=51
Probability of question Incorrect =45=\frac {4}{5}=54
Probability get at least six questions correct
=10C6(15)6(45)4+10C7(15)7(45)3+10C8(15)8(45)2+10C9(15)9(45)1+10C10(15)10(45)0=10C_{6} (\frac{1}{5})^6(\frac {4}{5})^4 +10C_{7} (\frac{1}{5})^7(\frac {4}{5})^3+10C_{8} (\frac{1}{5})^8(\frac {4}{5})^2+10C_{9} (\frac{1}{5})^9(\frac {4}{5})^1+10C_{10} (\frac{1}{5})^{10} (\frac {4}{5})^0=10C6(51)6(54)4+10C7(51)7(54)3+10C8(51)8(54)2+10C9(51)9(54)1+10C10(51)10(54)0
=6.3739×10−3= 6.3739 \times 10 ^{-3}=6.3739×10−3
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