Answer to Question #119445 in Statistics and Probability for desmond

Question

The mean number of errors due to a bug occurring in a minute is 0.0001. What is the
probability that no error will occur in 20 minutes?

Answer 1

$\lambda\; per\; 20\; minute =20\times 0.0001=0.002\\ P(X=0)=\frac{e^{-0.002}(0.002)^{0}}{0!}\approx0.998$