The aim is to compute "P(X>0)". We remind that for the Poisson distribution with the mean equal to "0.4" we have
"P(X=k)= \\frac{(0.4)^{k}}{k!}e^{-0.4}."
Thus, using the Taylor series for the exponent, we have
"P(X>0)=\\sum_{k=1}^{+\\infty} \\frac{(0.4)^{k}}{k!}e^{-0.4}=e^{-0.4}(e^{0.4}-1)=0.3297"
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