"Given \\; that, \u03bc=55, \u03c3^{2}=25, \u03c3=5,then,\\\\\n a) P(46<x<55) = P(\\frac{46-55}{5}< Z <\\frac{55-55}{5})\\\\\n=P(-1.8<Z<0)\\\\= P(0<Z<1.8)=0.4641\\\\\n b) P(50<x<58) = P(\\frac{50-55}{5}< Z <\\frac{58-55}{5})\\\\\n=P(-1<Z<0.6)\\\\\n= P(0<Z<1)+ P(0<Z<0.6)\\\\\n=0.3413+0.2257=0.567"
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