"Given \\; that, \u03bc=56, \u03c3=7,then,\\\\\n a) P(x>60) = P( Z >\\frac{60-56}{7})\\\\\n=P(Z>0.57)\\\\= 0.5-P(0<Z<0.57)\\\\\n=0.5-0.2157=0.2843\\\\\nb) P(x<50) = P( Z <\\frac{50-56}{7})\\\\\n=P(Z<-0.86)\\\\= 0.5-P(0<Z<0.86)\\\\\n=0.5-0.3051=0.1949\\\\"
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