Question

. Find the area under the standard normal distribution which lies between Z = -0.45 and Z = 0.75?

Answer 1

Solution: solve this with Laplace function $\Phi$ and using a table of Laplace function values.

$\int_{-0.45}^{0.75} \frac{1}{\sqrt{2\pi}}e^{\frac{-x^2}{2}} = \Phi(0.75)-\Phi(-0.45)\approx0.2734+0.1736=0.457$

Answer: 0.457