(a) The probability mass function of the number of bulls that the archer hits.
P(x)=C96x(132)x(3132)96−xP(x)=C_{96}^x (\frac{1}{32})^x(\frac{31}{32})^{96-x}P(x)=C96x(321)x(3231)96−x
(b) Using the Poisson approximation with λ=np=96∗(1/32)=3λ=np=96∗ (1/32) =3λ=np=96∗(1/32)=3
P(X≤1)=P(X=0)+P(X=1)=e−λ+λe−λ=e−3+3e−3=0.1991P(X\le1)=P(X=0)+P(X=1)=e^{-\lambda}+\lambda e^{-\lambda}=e^{-3}+3e^{-3}=0.1991P(X≤1)=P(X=0)+P(X=1)=e−λ+λe−λ=e−3+3e−3=0.1991
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