(a) The probability mass function of the number of bulls that the archer hits.
"P(x)=C_{96}^x (\\frac{1}{32})^x(\\frac{31}{32})^{96-x}"
(b) Using the Poisson approximation with "\u03bb=np=96\u2217 \n(1\/32)\n\u200b\t\n =3"
"P(X\\le1)=P(X=0)+P(X=1)=e^{-\\lambda}+\\lambda e^{-\\lambda}=e^{-3}+3e^{-3}=0.1991"
Comments
Leave a comment