Question

A package of 6 fuses are tested where the probability an individual fuse is defective is 0.5
What is the probability that one fuse will be defective

Answer 1

Binomial distribution problem with $P=0.05$ and $n=6$

$P(=1) =0.05 \times{(1-0.05)^5} \times {6}=0.2321342$