Question #116175
The average grade/mark of all college students is 70 with standard deviation of 20. If a random sample of 49 students is taken, what is the probability that the sample average grade/mark is
a) At least 65
b) Less than 78
c) Between 65 and 72
1
Expert's answer
2020-05-19T18:55:45-0400

Given  thatxˉ=70,s=20,n=49(a)P(xˉ>65)=P(Z>65702049)=P(Z>1.75)=0.5+P(0<Z<1.75)=0.5+0.4599=0.9599(b)P(xˉ<78)=P(Z<78702049)=P(Z<2.8)=0.5+P(0<Z<2.8)=0.5+0.4974=0.9974(c)P(65<xˉ<72)=P(65702049)<Z<72702049)=P(1.75<Z<0.7)=P(0<Z<1.75)+P(0<Z<0.7)=0.4599+0.2580=0.7179Given\;that\, \bar x=70,s=20,n=49\\ (a) P(\bar x>65)=P(Z>\frac{65-70}{\frac{20}{\sqrt{49}}})\\ =P(Z>-1.75)=0.5+P(0<Z<1.75)\\ =0.5+0.4599=0.9599\\ (b) P(\bar x<78)=P(Z<\frac{78-70}{\frac{20}{\sqrt{49}}})\\ =P(Z<2.8)=0.5+P(0<Z<2.8)\\ =0.5+0.4974=0.9974\\ (c)P(65<\bar x<72)=P(\frac{65-70}{\frac{20}{\sqrt{49}}})<Z<\frac{72-70}{\frac{20}{\sqrt{49}}})\\ =P(-1.75<Z<0.7)\\ =P(0<Z<1.75)+P(0<Z<0.7)\\ =0.4599+0.2580=0.7179\\


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS