Question #116165
A package of 6 fuses are tested where the probability an individual fuse is defective is 0.05 that is 5% of all fuses manufactured are defective . (a) . What is tue probability at least one fuse will be defective ? (b) . What is tue probability that more than one fuse will be defective given that at level one is defective ?
1
Expert's answer
2020-05-19T14:09:03-0400

Binomial distribution problem with P=0.05P=0.05 and n=6n=6

(a). P(1)P(1\le)

P(1)=1P(=0)P(1\le)=1-P(=0)

P(=0)=(10.05)6=0.735092P(=0) = (1-0.05)^6=0.735092

P(1)=10.735092=0.264908P(1\le)=1-0.735092=0.264908

(b). P(1<1)P(1<|1\le)

P(>11)=P(>1)/P(1)P(>1|≥1)=P(>1)/P(≥1)

P(>1)=1P(=0)P(=1)=10.7350.232=0.033P(>1)=1-P(=0)-P(=1)=1-0.735-0.232=0.033

P(>11)=0.033/0.265=0.124P(>1|≥1)=0.033/0.265=0.124


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